If it's not what You are looking for type in the equation solver your own equation and let us solve it.
D( x )
a^2 = 0
a^2 = 0
a^2 = 0
a^2 = 0
x należy do R
x belongs to the empty set
x = 3-a-((3*a)/(a^2))-1
x belongs to the empty set
| 4(2z+9)=18-2(z-9) | | (a^2y^2/a^3y^-7)^10 | | 2/3m/5=37/15 | | -2x+6=x+4 | | 50=n+(-28) | | 2(5k+3)-15k+8+4= | | [(6x^-3*y^4)/(3x^5y^-7)]^4 | | 4(2r+9)=3r-14 | | 0.5(23-y)=4y+16 | | 5(m-1)=5 | | -3=2/5 | | 5n+2-6=-3 | | 10x^3-15x^2-16x+12=0 | | 7l+1=36 | | (x-3)+(x+8)+(x+5)+x=360 | | 9(8z+3)=8(9z-6)+19 | | .6x=-4 | | 12x^4/3x^2 | | 50=-2+13j | | (7x^2/4y^3)/(4x/3y^2) | | 2-15=5(-3+2) | | 2y-18=165 | | 45x=303 | | 25x=4 | | 2d-5=-3 | | 10c+3=6c-15 | | sin^2(x)+sin(x)-6=0 | | 44+2x=64 | | 7u-4(3u-5)=80 | | 6=6-5b-3b | | 5(x+3)=3x-2 | | 5(v+1)=2(1-3w)-8 |